8ft x3ftx1 2 steel plate weight,Calculating the Weight of an 8ft x 3ft x 12" Steel Plate When it comes to figuring out the weight of an 8 - foot by 3 -
Calculating the Weight of an 8ft x 3ft x 12" Steel Plate
When it comes to figuring out the weight of an 8 - foot by 3 - foot by 12 - inch steel plate, we need to know a few things. First, we need to know the density of steel. The density of steel is typically around 490 pounds per cubic foot. Now, let's calculate the volume of our steel plate.
The volume of a rectangular prism (which is what our steel plate is shaped like) is calculated by multiplying the length, width, and height. Our length is 8 feet, the width is 3 feet, and the height (or thickness in this case) is 1 foot (since 12 inches is equal to 1 foot). So the volume V = 8ft×3ft×1ft = 24 cubic feet.
To find the weight, we multiply the volume by the density. So the weight W = 24 cubic feet×490 pounds per cubic foot = 11760 pounds. So, an 8ft x 3ft x 12" steel plate weighs 11760 pounds.
Question 1: How can I calculate the weight of an 8ft x 3ft x 12" steel plate?Answer: First, find the volume of the plate by multiplying the length (8ft), width (3ft) and height (1ft, as 12 inches = 1ft), which gives 24 cubic feet. Then multiply the volume by the density of steel (about 490 pounds per cubic foot), so the weight is 11760 pounds.
Question 2: What is the volume of an 8ft x 3ft x 12" steel plate?Answer: The volume is found by multiplying the length, width and height. So it is 8ft×3ft×1ft = 24 cubic feet.
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